(p^2-4p-3)(p+1)=0

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Solution for (p^2-4p-3)(p+1)=0 equation:


Simplifying
(p2 + -4p + -3)(p + 1) = 0

Reorder the terms:
(-3 + -4p + p2)(p + 1) = 0

Reorder the terms:
(-3 + -4p + p2)(1 + p) = 0

Multiply (-3 + -4p + p2) * (1 + p)
(-3(1 + p) + -4p * (1 + p) + p2(1 + p)) = 0
((1 * -3 + p * -3) + -4p * (1 + p) + p2(1 + p)) = 0
((-3 + -3p) + -4p * (1 + p) + p2(1 + p)) = 0
(-3 + -3p + (1 * -4p + p * -4p) + p2(1 + p)) = 0
(-3 + -3p + (-4p + -4p2) + p2(1 + p)) = 0
(-3 + -3p + -4p + -4p2 + (1 * p2 + p * p2)) = 0
(-3 + -3p + -4p + -4p2 + (1p2 + p3)) = 0

Combine like terms: -3p + -4p = -7p
(-3 + -7p + -4p2 + 1p2 + p3) = 0

Combine like terms: -4p2 + 1p2 = -3p2
(-3 + -7p + -3p2 + p3) = 0

Solving
-3 + -7p + -3p2 + p3 = 0

Solving for variable 'p'.

The solution to this equation could not be determined.

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